I think it's working fine in the series as part of the dataframe, but I'm still struggling with inserting it into the Matplotlib title. I have created a new column with df["weekday"] = df["Date"].dt.weekday, and changed the title section to plt.title(date, df['weekday']) and it returned TypeError: pop() takes 2 positional arguments but 3 were ...
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## Here is a potential solution with using UDF which can solve the issue. # UDF’s are a black box to PySpark as it can’t apply any optimization and you # will lose all the optimization PySpark does on Dataframe. so you should use # Spark SQL built-in functions as these functions provide optimization.
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(weekday + 5) % 7 + 1 If you decide to use this, it would be worth running through some examples to convince yourself that it actually does what you want. addition: for not to be affected by the DATEFIRST variable (it could be set to any value between 1 and 7) the real formula is : (weekday + @@DATEFIRST + 5) % 7 + 1
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I want to get the day of week from the Java Date object when I have an array of Date in String with me. SimpleDateFormat sourceDateformat = new SimpleDateFormat("yyyy-MM-dd"); public String
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I was having problems while using the datetime library because I wanted to store the weekday name instead of weekday number and the format from using the datetime library was causing problems. If you're not having problems with this, great! If you are, you cand efinitely go for this as it has a simpler syntax as well. Hope this helps.
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I would like to get the weekday name for all my date. I have a pandas df which has a Date column formatted to datetime64[ns] i have tried the following. data['Date'].dt.weekday_name and I get the response
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To get a deterministic value for the day of week for a given date you could use a combination of DATEPART () and @@datefirst. Otherwise your dependent on the settings on the server. Check out the following site for a better solution: MS SQL: Day of Week. The day of week will then be in the range 0 to 6, where 0 is Sunday, 1 is Monday, etc.
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As pointed out to me by user @joris you can just access the weekday attribute of the index so the following will work and is more compact: df['Weekday'] = df.index.weekday Share
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Given dayNumber is from 0 - 6 representing Monday - Sunday respectively. Can the Date / String objects be used to get the day of the week from dayNumber?
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to do this in oracle sql, i tried like this and it worked for me. select start_date, case when start_day = 7 then 'sunday' when start_day = 1 then 'monday' when start_day = 2 then 'tuesday' when start_day = 3 then 'wednesday' when start_day = 4 then 'thursday' when start_day = 5 then 'friday' when start_day = 6 then 'saturday' end day_name from (select to_char(t.start_date, 'dy') start_day, to ...
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